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發問:
1.balculate the rms speeds at 20℃ of atoms of:(A)helium (4u);(B)neon (20u);(C)radon (222u). 2.the temperature in the intreior of the sun is about 2 ＊(10^7) K.what is (A)the average kinetic... 顯示更多 1.balculate the rms speeds at 20℃ of atoms of:(A)helium (4u);(B)neon (20u);(C)radon (222u). 2.the temperature in the intreior of the sun is about 2 ＊(10^7) K.what is (A)the average kinetic energy,and(B)the rms speed of protons?
最佳解答:
1) Using the formula: crms = √(3kT/m) where k = Boltzmann's constant T = Absolute temperature m = Mass of the particle So crms of helium atoms = √(3 × 1.38 × 10-23 × 293/4 × 1.66 × 10-27) = 1352 m/s crms of neon atoms = √(3 × 1.38 × 10-23 × 293/20 × 1.66 × 10-27) = 604 m/s crms of helium atoms = √(3 × 1.38 × 10-23 × 293/222 × 1.66 × 10-27) = 181 m/s 2) Mass of proton = 1u. So Average kinetic energy = (3/2)kT = (3/2) × 1.38 × 10-23 × 2 × 107 = 4.412 × 10-16 J crms of a protons = √(3 × 1.38 × 10-23 × 2 × 107 /1.66 × 10-27) = 7.063 × 105 m/s
其他解答:
you can refer to your another post on [kinetic interpretation of pressure]
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kinetic theory??發問:
1.balculate the rms speeds at 20℃ of atoms of:(A)helium (4u);(B)neon (20u);(C)radon (222u). 2.the temperature in the intreior of the sun is about 2 ＊(10^7) K.what is (A)the average kinetic... 顯示更多 1.balculate the rms speeds at 20℃ of atoms of:(A)helium (4u);(B)neon (20u);(C)radon (222u). 2.the temperature in the intreior of the sun is about 2 ＊(10^7) K.what is (A)the average kinetic energy,and(B)the rms speed of protons?
最佳解答:
1) Using the formula: crms = √(3kT/m) where k = Boltzmann's constant T = Absolute temperature m = Mass of the particle So crms of helium atoms = √(3 × 1.38 × 10-23 × 293/4 × 1.66 × 10-27) = 1352 m/s crms of neon atoms = √(3 × 1.38 × 10-23 × 293/20 × 1.66 × 10-27) = 604 m/s crms of helium atoms = √(3 × 1.38 × 10-23 × 293/222 × 1.66 × 10-27) = 181 m/s 2) Mass of proton = 1u. So Average kinetic energy = (3/2)kT = (3/2) × 1.38 × 10-23 × 2 × 107 = 4.412 × 10-16 J crms of a protons = √(3 × 1.38 × 10-23 × 2 × 107 /1.66 × 10-27) = 7.063 × 105 m/s
其他解答:
you can refer to your another post on [kinetic interpretation of pressure]
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