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Math question
發問:
1) during a closing down sale , a watch was sold at $143. the shopkeeper made a loss of 35% on the price he paid for it . Calculate his cost price for the watch .2) two similar solids have a base areas of 28 cm^2 and 63 cm^2 .find the mass of the larger soild if the mass of the smaller solid is... 顯示更多 1) during a closing down sale , a watch was sold at $143. the shopkeeper made a loss of 35% on the price he paid for it . Calculate his cost price for the watch . 2) two similar solids have a base areas of 28 cm^2 and 63 cm^2 .find the mass of the larger soild if the mass of the smaller solid is 160g. 3)sector A , with an area of 150cm^2 is cut out from a piece of paper.find the area of sector B ,with twice the radius r ,of sector A but half the size of angle x .
最佳解答:
1) During a closing down sale, a watch was sold at $143. the shopkeeper made a loss of 35% on the price he paid for it. Calculate his cost price for the watch. Method 1: Let $y be the cost price of the watch. y(1 - 35%) = 143 y = 220 Cost price of the watch = $220 Method 2: Cost price of the watch = $143 ÷ (1 - 35%) = $220 ===== 2) Two similar solids have a base areas of 28 cm2 and 63 cm2. Find the mass of the larger solid if the mass of the smaller solid is 160g. (Radius of the smaller solid) : (Radius of the larger solid) = √28 : √63 = 2√7 : 3√7 = 2 : 3 (Mass of the smaller solid) : (Mass of the larger solid) = (Volume of the smaller solid) : (Volume of the larger solid) = 23 : 33 = 8 : 27 Mass of the larger solid = 160 x (27/8) g = 540 g ===== 3) Sector A , with an area of 150 cm2 is cut out from a piece of paper. Find the area of sector B, with twice the radius r ,of sector A but half the size of angle x. Area of sector A: πr2(x/360) = 150 Area of sector B = π(2r)2[(x/2)/360] cm2 = 2πr2(x/360) cm2 = 2(150) cm2 = 300 cm2
其他解答:
Math question
發問:
1) during a closing down sale , a watch was sold at $143. the shopkeeper made a loss of 35% on the price he paid for it . Calculate his cost price for the watch .2) two similar solids have a base areas of 28 cm^2 and 63 cm^2 .find the mass of the larger soild if the mass of the smaller solid is... 顯示更多 1) during a closing down sale , a watch was sold at $143. the shopkeeper made a loss of 35% on the price he paid for it . Calculate his cost price for the watch . 2) two similar solids have a base areas of 28 cm^2 and 63 cm^2 .find the mass of the larger soild if the mass of the smaller solid is 160g. 3)sector A , with an area of 150cm^2 is cut out from a piece of paper.find the area of sector B ,with twice the radius r ,of sector A but half the size of angle x .
最佳解答:
1) During a closing down sale, a watch was sold at $143. the shopkeeper made a loss of 35% on the price he paid for it. Calculate his cost price for the watch. Method 1: Let $y be the cost price of the watch. y(1 - 35%) = 143 y = 220 Cost price of the watch = $220 Method 2: Cost price of the watch = $143 ÷ (1 - 35%) = $220 ===== 2) Two similar solids have a base areas of 28 cm2 and 63 cm2. Find the mass of the larger solid if the mass of the smaller solid is 160g. (Radius of the smaller solid) : (Radius of the larger solid) = √28 : √63 = 2√7 : 3√7 = 2 : 3 (Mass of the smaller solid) : (Mass of the larger solid) = (Volume of the smaller solid) : (Volume of the larger solid) = 23 : 33 = 8 : 27 Mass of the larger solid = 160 x (27/8) g = 540 g ===== 3) Sector A , with an area of 150 cm2 is cut out from a piece of paper. Find the area of sector B, with twice the radius r ,of sector A but half the size of angle x. Area of sector A: πr2(x/360) = 150 Area of sector B = π(2r)2[(x/2)/360] cm2 = 2πr2(x/360) cm2 = 2(150) cm2 = 300 cm2
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