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maths.Q
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Find x : 3^(3x+2)+27^(x+1) =12
最佳解答:
3^(3x+2)+27^(x+1) =12 3^(3x+2)+3^[3(x+1)] =12 (27 = 3^3) 3^(3x+2) +3^(3x + 3) =12 3^(3x + 2) + 3 x 3^(3x + 2) = 12 3^(3x + 2) x (1 + 3) = 12 (3^(3x + 2) is the common factor) 3^(3x + 2) = 3 3x + 2 = 1 3x = -1 x = -1/3
其他解答:
3^(3x+2)+27^(x+1) =12 3^(3x+2)+3^3[^(x+1)] =12 3^(3x+2)+3^(3x+3)=12 3^(3x+2) x (1+3)=12 3^(3x+2) =12/4=3=3^1 3x+2=1 x=-1/3
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