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標題:
Physics Optics
發問:
A 2m long vertical pipe extends from the bottom of a swimming pool to a point 50 cm above the surface of the water. Sunlight is incident on the water at angle of 55 degree to the normal. what is the length of the shadow of the pipe on the bottom of the pool? the refractvie index of water is n=1.33.
Distance of the shadow of the top of the pipe on water surface = 0.5/tan(35) m sin(r) = sin(55)/1.33, where r is the angle of refraction From geometry, the distance of the shadow of the top of the pole on the bottom of the pool = [1.5tan(r) + 0.5/tan(35)] m
其他解答:
Physics Optics
發問:
A 2m long vertical pipe extends from the bottom of a swimming pool to a point 50 cm above the surface of the water. Sunlight is incident on the water at angle of 55 degree to the normal. what is the length of the shadow of the pipe on the bottom of the pool? the refractvie index of water is n=1.33.
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最佳解答:Distance of the shadow of the top of the pipe on water surface = 0.5/tan(35) m sin(r) = sin(55)/1.33, where r is the angle of refraction From geometry, the distance of the shadow of the top of the pole on the bottom of the pool = [1.5tan(r) + 0.5/tan(35)] m
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