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標題:
發問:
1)a+b(3+a)=27 b*4+a(2+b)=36 a=? b=?
最佳解答:
1) a + b(3+a) = 27 a + 3b + ab = 27......(1) b*4 + a(2+b) = 36 2a + 4b + ab = 36.....(2) (2) - (1) : a + b = 9 a = (9-b),sub to (1): (9 - b) + 3b + b(9 - b) = 27 9 + 2b + 9b - b^2 = 27 b^2 - 11b + 18 = 0 (b - 2)(b - 9) = 0 b = 2 or b = 9 so a + 2 = 9 or a + 9 = 9 a = 7 or a = 0 So when a = 7 , b = 2 when a = 0 , b = 9
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MATH!!!!!!!!代數發問:
1)a+b(3+a)=27 b*4+a(2+b)=36 a=? b=?
最佳解答:
1) a + b(3+a) = 27 a + 3b + ab = 27......(1) b*4 + a(2+b) = 36 2a + 4b + ab = 36.....(2) (2) - (1) : a + b = 9 a = (9-b),sub to (1): (9 - b) + 3b + b(9 - b) = 27 9 + 2b + 9b - b^2 = 27 b^2 - 11b + 18 = 0 (b - 2)(b - 9) = 0 b = 2 or b = 9 so a + 2 = 9 or a + 9 = 9 a = 7 or a = 0 So when a = 7 , b = 2 when a = 0 , b = 9
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