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標題:
math 急用
發問:
1) The sum and difference of 2 numbers are 37 and 3 respectively. find their product. 2) A metallic cyclinder of radius 10 cm is melted and reformed to 2 smaller identical cylinders while the height is kept unchanged. find the radius of a smaller cylinder.
最佳解答:
1) Let the two numbers be x and y (x>y) x+y=37...(1) x-y=3...(2) (1)-(2): 2y=34 y=17 and x=3+17=20 So, their product=xy=20*17=340. 2) Let the height of the original cyclinder be h cm and the radius of small cyclinder be r cm pi*10^2*h=2(pi*r^2*h) 10^2=2*r^2 r^2=50 r=√50=√25*√2=5√2 So, the required radius is 5√2 cm
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