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***Please show all workings, even very easy!! It's worth to answer, u gonna get Double Score if your answer is perfect!!!so u can get 20 if your answer is attempted!!! Q1)x=(t^2)-2t ----- equation1y=(t^2)+2 ----- equation2Ans: (y-x)^2-4(2y-x)+12=0 Q2)x=3(t+1/t) ---- equation1y=4(t-1/t) -----... 顯示更多 ***Please show all workings, even very easy!! It's worth to answer, u gonna get Double Score if your answer is perfect!!! so u can get 20 if your answer is attempted!!! Q1) x=(t^2)-2t ----- equation1 y=(t^2)+2 ----- equation2Ans: (y-x)^2-4(2y-x)+12=0 Q2) x=3(t+1/t) ---- equation1 y=4(t-1/t) ----- equation2Ans: (x^2)/36 - (y^2)/64 = 1
最佳解答:
Well, you can attempt in the ways below by trying to eliminate the existence of "t" in two equations and combine them into one: 1) x = t^2 - 2t and y = t^2 + 2 Hence, x = ( y - 2 ) - 2t ( x - y + 2 ) = -2t ( x - y + 2 )^2 = 4t^2 = 4( y - 2 ) [ ( x - y ) + 2 ]^2 = 4( y - 2 ) ( x - y )^2 + 4( x - y ) + 4 = 4y - 8 ( x - y )^2 + 4( x - 2y ) + 12 = 0 ( y - x )^2 - 4( 2y - x ) + 12 = 0 ========================= 2) x = 3( t + 1/t ) x^2 = 9( t^2 + 2 + 1/t^2 ) y = 4( t - 1/t ) y^2 = 16( t^2 - 2 + 1/t^2 ) Solve by elimination method: 16 x^2 - 9 y^2 = 144 ( t^2 + 2 + 1/t^2 ) - 144 ( t^2 - 2 + 1/t^2 ) = 576 Hence, divide both sides by 576, we have x^2/36 - y^2 / 64 = 1 ================= Hope I can help you.
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