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標題:
發問:
(-1/27)^1/3 + 4^-1/2 (-1/2)^-3 x (1/4)^-1 除(1/2^3)^-1 ^x =x次方
最佳解答:
(-1/27)1/3 + 4-1/2 [(-1)3]1/3/[33]1/3 + 1/[41/2] = -1/3 + 1/[22]1/2 = -1/3 + 1/2 = -2/6 + 3/6 = 1/6 ============================ (-1/2)-3 × (1/4)-1 ÷ (1/23)-1 = 1/[(-1/2)3] × 1/[(1/4)1] ÷ 1/[(1/23)1] = 1/[(-1)3/(2)3] × 1/[(1/4)] ÷ 1/[(1/23)] = 1/[-1/8] × 4 ÷ 1/[(1/8)] = 8/(-1) × 4 ÷ 8 = -8 × 4 ÷ 8 = -1 2006-12-07 15:19:04 補充： 對不起，第二題最後一行打錯了，應該是「= -4」 2006-12-07 16:13:36 補充： 小小補充：指數題目要注意的公式有：a^(-b) = 1/(a^b)a^(b+c) = (a^b)(a^c)a^(b-c) = (a^b)/(a^c)[a^(b^c)] = (a^b)^c
其他解答:
(-1/27)^1/3+4^-1/2 =(3^-1/3)^1/3+(2^2)^-1/2 =3^-1/9+2^-1 (-1/2)^-3*(1/4)^-1/(1/2^3)^-1 =(2^-1)^-3*(2^-2)^-1/(2^-3)^-1 =2^3*2^2/2^3 =4 唔知啱唔啱|||||1)1/6 2)-4
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點樣計嫁?!?!?發問:
(-1/27)^1/3 + 4^-1/2 (-1/2)^-3 x (1/4)^-1 除(1/2^3)^-1 ^x =x次方
最佳解答:
(-1/27)1/3 + 4-1/2 [(-1)3]1/3/[33]1/3 + 1/[41/2] = -1/3 + 1/[22]1/2 = -1/3 + 1/2 = -2/6 + 3/6 = 1/6 ============================ (-1/2)-3 × (1/4)-1 ÷ (1/23)-1 = 1/[(-1/2)3] × 1/[(1/4)1] ÷ 1/[(1/23)1] = 1/[(-1)3/(2)3] × 1/[(1/4)] ÷ 1/[(1/23)] = 1/[-1/8] × 4 ÷ 1/[(1/8)] = 8/(-1) × 4 ÷ 8 = -8 × 4 ÷ 8 = -1 2006-12-07 15:19:04 補充： 對不起，第二題最後一行打錯了，應該是「= -4」 2006-12-07 16:13:36 補充： 小小補充：指數題目要注意的公式有：a^(-b) = 1/(a^b)a^(b+c) = (a^b)(a^c)a^(b-c) = (a^b)/(a^c)[a^(b^c)] = (a^b)^c
其他解答:
(-1/27)^1/3+4^-1/2 =(3^-1/3)^1/3+(2^2)^-1/2 =3^-1/9+2^-1 (-1/2)^-3*(1/4)^-1/(1/2^3)^-1 =(2^-1)^-3*(2^-2)^-1/(2^-3)^-1 =2^3*2^2/2^3 =4 唔知啱唔啱|||||1)1/6 2)-4
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