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Math question(S2)

發問:

1. For two consecutive multiples of 5, the smaller number is greater than half of the larger one. Find the least values of these two number. 2.x is greater than y by 5,and the sum of x and y is less that 49. Find the largest value of x if x is an integer.

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1.Let the smaller consecutive multiples of 5 is x. The bigger one is x+5 x小於(x+5)/2 2x小於x+5 x小於5 so the least values of these two number are 10 and (10+5)=15. 2.x大於y+5...(1) x+y小於49...(2) From(1), y小於x-5 Sub (1) into (2), x+x-5小於49 2x小於54 x小於27 so the largest value of x is 26.

其他解答:

第一條唔知 第二條X係27 Y係21 可能唔對|||||1 let the two number be x and x+1 5x>(x+1)*5 / 2 5x>2.5x+2.5 2.5x>2.5 x>1 the least values of these two number are 2 and 3 (2+1) 2, x = y+5,代入xy<49 (y+5)*y <49 y<5 the largest value of x is 4 2008-06-05 19:46:05 補充： > 等於大於 < 等於小於 2008-06-05 19:46:55 補充： >等於大於 <等於小於 顯示唔到
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