標題:
數學題目~...幫幫我解答,thx
發問:
ｙ隨ａ既立方而正變，且隨ｂ而反變。如果ａ同ｂ都增加２０％，求ｙ既百分變化 [請詳解/列式]
最佳解答:
Let y = ka^3/b Now, a' = a(1+20%) = 1.2a b' = b(1+20%) = 1.2b y' = ka'^3/b' = k(1.2a)^3/(1.2b) = (1.2)^2 (ka^3/b) = 1.44 y % change in y = (y'-y)/y * 100% = (1.44y-y)/y*100% = 0.44*100% =44% (increase)
其他解答:
等我話比你知啦!!!!!! 就係咁嫁........ Let y = ka^3/b Now, a' = a(1+20%) = 1.2a b' = b(1+20%) = 1.2b y' = ka'^3/b' = k(1.2a)^3/(1.2b) = (1.2)^2 (ka^3/b) = 1.44 y % change in y = (y'-y)/y * 100% = (1.44y-y)/y*100% = 0.44*100% =44% (increase)|||||設y=ka^3/b,則ａ同ｂ都增加２０％時,有 y=k(1.2a)^3/1.2b =ka^3*1.2^3/1.2b =ka^3*1.2^2/b =1.44(ka^3/b) =ka^3/b+0.44(ka^3/b) 所以如果ａ同ｂ都增加２０％，ｙ既百分變化44％
數學題目~...幫幫我解答,thx
發問:
ｙ隨ａ既立方而正變，且隨ｂ而反變。如果ａ同ｂ都增加２０％，求ｙ既百分變化 [請詳解/列式]
最佳解答:
Let y = ka^3/b Now, a' = a(1+20%) = 1.2a b' = b(1+20%) = 1.2b y' = ka'^3/b' = k(1.2a)^3/(1.2b) = (1.2)^2 (ka^3/b) = 1.44 y % change in y = (y'-y)/y * 100% = (1.44y-y)/y*100% = 0.44*100% =44% (increase)
其他解答:
等我話比你知啦!!!!!! 就係咁嫁........ Let y = ka^3/b Now, a' = a(1+20%) = 1.2a b' = b(1+20%) = 1.2b y' = ka'^3/b' = k(1.2a)^3/(1.2b) = (1.2)^2 (ka^3/b) = 1.44 y % change in y = (y'-y)/y * 100% = (1.44y-y)/y*100% = 0.44*100% =44% (increase)|||||設y=ka^3/b,則ａ同ｂ都增加２０％時,有 y=k(1.2a)^3/1.2b =ka^3*1.2^3/1.2b =ka^3*1.2^2/b =1.44(ka^3/b) =ka^3/b+0.44(ka^3/b) 所以如果ａ同ｂ都增加２０％，ｙ既百分變化44％
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