標題:

aa.jpg

 

此文章來自奇摩知識+如有不便請留言告知

From.1's Maths

發問:

1]]20 minus the product of a number and 2 is equal to the square of 4.Find the number. 2]The sum of three consecutive even nunbers is 42.Find the three numbers.

最佳解答:

1) Let x be the required number. 20-2x=4^2 20-2x=16 2x=4 x=2 Hence, the required number is 2. 2) Let x-2,x,x+2 be the three consecutive even numbers. (x-2)+x+(x+2)=42 3x=42 x=14 Hence, the three required consecutive even numbers are 12, 14 and 16.

其他解答:

1. 20 - 2a = 4^2 20 - 2a = 16 2a = 4 a = 2 2. let x be the first consecutive even nunber, (x + 2) be the second consecutive even nunber, (x + 4) be the third consecutive even nunber x + (x + 2) + (x + 4) = 42 3x + 6 = 42 3x = 36 x = 12 Therefore, three consecutive even nunbers are 12, 14 and 16.|||||第2條: let x be a small no, x+x+2+x+4=42 3x+6=42 x=12 所以the three consecutive even numbers are 12,14,16. 唔知對唔對!!!!!|||||1]]Let X be the number. 2 20-2X=4 20-2X=16 20-16=2X 4=2X 4/2=X X=2 So the number is 2. 2]]Let X be the number. X+(X+1)+(X+2)=42 3X+3=42 3X=42-3 3X=39 X=39/3 X=13 So the number is 13.|||||1. let x be the number 20-2x=4^2 20-16= 2x 4=2x x=2 2. let x be first no. , (x+2) be second no. and (x+4)be third no. x+(x+2)+(x+4)=42 x+x+2+x+4=42 3x=42-4-2 3x=36 x=12 so the first no.x=12,second no.=x+2= 14 and the third no. x+4 =16|||||let n be the number .................2 1.20-n+2=4 2.n+1+n+2+n+3=42|||||1) 20-2a=4×4 20-2a=16 a=2 2) y+(y+2)+(y+4)=42 3y+6=42 3y=36 y=12|||||第2條" let x be the smallest number x+x+1+x+2=42 3x+3 =42 3x=42-3 3x =39 x=13 ∴the numbers are 13,14,15. 第1條(唔知岩唔岩) let the number be x 20-x-2=4square 20-x-2=4×4 18-x =16 -x =-2 x=2 ∴the number is 2
arrow
arrow
    文章標籤
    公主 文章 奇摩
    全站熱搜

    gbu94mz95e 發表在 痞客邦 留言(0) 人氣()