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3條數學題(英文題目)

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Question 1Consider a rectangular as shown below:圖片參考：http://i181.photobucket.com/albums/x37/Destiny_homan/Question1.png(a) Assume the area of the rantangular is S, write down an equation of a and S.(b) Rewrite the equation is S to the form of a quadratic equation in a.(c) Hence, slove the equation for a by... 顯示更多 Question 1 Consider a rectangular as shown below: 圖片參考：http://i181.photobucket.com/albums/x37/Destiny_homan/Question1.png (a) Assume the area of the rantangular is S, write down an equation of a and S.(b) Rewrite the equation is S to the form of a quadratic equation in a.(c) Hence, slove the equation for a by completeing the sqaure. Express your answers in terms of S.(d) If S = 30, find a.Question 2 A gas has a volume of 300cc at 15oC and a volume of 450cc at 30oC. The volume and temperature of any gas vary in a linear fashion.(a) Use this two data points to write an equation relating the volume and temperature of this gas (y=volume,x=temperature)(b) At what temperature will the volume be 0?(c) Sketch the graph of the equation for y 0only. Indicate the x-intercept, y-intercept, and the points im part (a) in the graph.Question 3 圖片參考：http://i181.photobucket.com/albums/x37/Destiny_homan/Quetion3.png A shooter gains the highest score if his shot strikes the target at the central point, i.e. P. If his shot deviates from the central point, he scores less.(a) The shot hits point Q. Find the horizontal distance PQ, which os the deviation of the shot from the central point, Express your answer ym terms of a and b.(b) He takes a second trial and the result is even worse. He ends up hitting R. Find the horizontal distance PR. Express your answer in terms of b and c.(c) Hence, determine the distance between Q and R. Express your answer in terms of a, b and c.(d) If the shooter is 10m away from the central point of the target, while b and c are 12km and 13km respectively, find the distance between Q and R. Correct your answer to 2 decimal places.

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其他解答:

1a a(a+1)=S 1b a^2+a-S=0 1cby completeing the sqaure, (a+0.5)^2-S-0.25=0 1d (a+0.5)^2=30.25 .'. a=5