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03 mc ce maths Q.44

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03 mc ce maths Q.44 解釋比我聽

最佳解答:

44. D 44. Since AB:BC =3:2 AND PQ:QR =4:3 BC=2x,AB=3x QR=3y,PQ=4y ,where x and y are constants The two rectangles have the same perimeter so 2(2x+3x)=2(3y+4y) 5x=7y x=7y/5 so area of ABCD:area of PQRS =(3x)(2x):(4y)(3y) =x2:2y2 =(7y/5)2:2y2 =49y2/25:2y2 =49:50

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